Thursday, February 10, 2011


So here's the next thing that's gonna kill us:

It's called C/2010 X1, dubbed Elenin after its russian discoverer. It's going to be at it's closest with Earth sometime in October and we'll pass through it's orbit's intersection with ours later in November. Apparently, the media hasn't taken to it with enough enthusiasm, so it's probably the planet Nibiru and "they"(you know, them) don't want us to know about it(genius logic, I know). There is just so much wrong with these fellows' logic that I just had to demonstrate how bunk it is. Here's a rundown of their main points and explanation of just what's bloody wrong with them.

1. Initial calculations had it passing 8.8 AU from Earth, but they've been continually revised downwards to the current estimate of at least .15 AU. (, para. 1)

Not amazing, really. As better data became available, the orbit got refined. Same thing happens with pretty much any moving astronomical object we find. Also, .15 AU is close on an astronomical scale, but still pretty far away on a human scale, 22,439,680 km away, 59 times the distance to the moon. But I guess their big point is...

2.The comet will pass through the Oort Belt (?), changing it's orbit (to hit Earth of course) (, para. 1) or pulling asteroids with its gravity to pummel earth (, para. 1)

The Oort belt? Maybe you mean the Oort Cloud? But still, that couldn't be because 1. the Oort cloud is(may be) 50,000 AU away and 2. it has never been directly observed - it is still quite hypothetical. Perhaps they mean the asteroid belt? Anyway, addressing the first issue. On an astronomical scale, Earth is a very tiny target. Veeeeeery tiny. About 0.00000000569 square astronomical units* tiny. Compare that with 0.0707AU^2, the area of the circle calculated using the closest approach distance of .15 AU, Earth is 0.0000000805 times that area! The odds of Elenin being deflected towards Earth are too minuscule to even consider.

Now as to the comet pulling asteroids out of their orbit...that's rubbish. Comets weigh in around 10^13 - 10^14 kg (compared with Earth's 5.97x10^24). That's really not much, and definitely not enough to have much gravitational effect on any objects in the asteroid belt. But then there's the objection that this is no comet...more on that later.

3. We'll be pummeled to death by the material in the comet's tail when we pass through it in November (, para. 1)

Save for the comet disintegrating, I see no issue with the comet's tail. A comet's tail is composed of dust particles and perhaps small pebble-sized grains, definitely not enough to pose a serious threat to Earth.

But there's a whole lot more woo-woo associated with this...

tl;dw (crud like this is always tl): this vid says that when the comet, Earth and sun align sometime in March, the comet will magnetically interact with the Earth and make us flip over or something. I raised the objections I am about to share here on that video and was called a retard. Nice fellows, these catastrophist folks.

1. Magnetism is caused by iron. Comets do not have iron.

2. In-situ magnetic fields decay over time. The only reason Earth still possesses a magnetic field after 4.5 billion years is because of convection currents in its ferrous core. Comets, being cold objects cannot have molten iron. Any magnetic iron they might have had would have decayed long ago.

3.March is *around* the time of the equinox. At that point, the Earth's axis is perpendicular to the plane of the ecliptic. If there were any magnetic effect between the earth and the comet, you'd expect it to act on both poles simultaneously. Of course, Earth's magnetic field is slightly off center of the rotational axis, but not by much, and definitely not enough to be in alignment with the comet on the ecliptic.

4. Regarding the "3 degree shift in the south pole"...[apparently what caused the Chile earthquake last year] ??? Magnetic south? 'Cause that would have no effect whatsoever on the planet. If it were a literal shift in rotational axis we would definitely have seen muuuuch more damage. You haven't provided how long the shift took, but I can surmise it would have generated a respectable amount of radial velocity. The inertia experienced by the earth would have been *massive*, causing way more damage than just one little earthquake.

At this point, I saw the video poster's comment positing that Elenin is not just a comet, but something more. Some have said it is literally the Nibiru that has been long talked about. Some have even called it a brown dwarf. Well, there's something wrong with this. I don't think they (you know, them) could have hidden this from us. Something larger than Jupiter that far into the solar system would most definitely have thrown the orbits of all the planets into disarray. It would also be visible to the naked eye and we wouldn't need a frickin' telescope to see it.

Some suspicion seems to have been raised by the fact that the comet was discovered by an "amateur" on an 18-inch telescope and not by the larger observatories. People who raise this as an issue don't understand the workings of astronomy. Those larger observatories aren't sweeping the sky all willy-nilly looking for stuff. They are engaged in research, looking into specific corners of the sky, and are doing so for pretty much every moment of good observing time. Astronomical phenomena are being discovered by amateurs all the time - from asteroids to supernovae to - yes - comets, amateurs are nearly always at the forefront of discovery.

Another silly objetion is that the media have been too silent over this, therefore there is a conspiracy to keep knowledge of it away from us.

I don't think highly of conspiracy theories, but I'll grace this with a psy-ops agent worthy explanation. The comet will peak at magnitude 6-8...barely visible to the naked eye. So why should the media make a big hoopla about it? The media is always slow when picking up stuff like this anyway, so it may only be a matter of time. Unless, of course, they catch wind of this whole collision story, in which case they will be making quite the hoopla about it.

*(pi) x (radius of the earth in AU, approx. 0.0000426 AU)^2

1 comment:

  1. I hope a chunk of Elenin lands on the heads of everyone of those eletards.